On the Equilibrium among Silicon in Molten Iron, Blast Furnace Slag and H_2-H_2O Mixed Gas. II : Investigation of the Equilibrium of the Reaction (SiO_2)_<Al_2O_3-CaO(sat.)>+2H_2=Si+2H_2O

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Using a CaO crucible, the equilibrium of the following reaction was studied under the conditions of 2CaO・SiO_2, 3CaO・SiO_2, or CaO saturation in the temperature range from 1, 550゜to 1, 600℃ : (SiO_2)_<Al_2O_3-CaO(sat)>+2H_2=Si+2H_2O. (1) The equilibrium constant of the reaction (I) becomes as follows : K_<Si-H>=P^2_<H_2>・a_<SiO_2>/p^2_<H_2O>・Si%. (2) As was already reported In the previous paper K_<Si-H> is equal to K^S_<Si-H>. Thus, a_<SiO_2>^<***> in the molten SiO_2-CaO-Al_2O_3 ternary slag was calculated from the following equation : a_<SiO_2>= K^S_<Si-H>・Si%・P^2_<H_2O>/P^2_<H_2>. (3) Finally, the authors determined the liquidus line of 1, 550°and 1, 600℃ on the CaO side of SiO_2-CaO-Al_2O_3 ternary diagram from the equilibrium compositions of slag.
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